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-0.1x^2+31x-2000=0
a = -0.1; b = 31; c = -2000;
Δ = b2-4ac
Δ = 312-4·(-0.1)·(-2000)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{161}}{2*-0.1}=\frac{-31-\sqrt{161}}{-0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{161}}{2*-0.1}=\frac{-31+\sqrt{161}}{-0.2} $
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